1441256831447 has 4 divisors (see below), whose sum is σ = 1441295623560. Its totient is φ = 1441218039336.

The previous prime is 1441256831411. The next prime is 1441256831459. The reversal of 1441256831447 is 7441386521441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1441256831447 - 2¹⁶ = 1441256765911 is a prime.

It is a super-3 number, since 3×1441256831447³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1441256831395 and 1441256831404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1441256801447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19340273 + ... + 19414650.

It is an arithmetic number, because the mean of its divisors is an integer number (360323905890).

Almost surely, 2^{1441256831447} is an apocalyptic number.

1441256831447 is a deficient number, since it is larger than the sum of its proper divisors (38792113).

1441256831447 is an equidigital number, since it uses as much as digits as its factorization.

1441256831447 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38792112.

The product of its digits is 2580480, while the sum is 50.

The spelling of 1441256831447 in words is "one trillion, four hundred forty-one billion, two hundred fifty-six million, eight hundred thirty-one thousand, four hundred forty-seven".