Base | Representation |
---|---|
bin | 100000110001011011101110… |
… | …111011101011110010001011 |
3 | 200220100010101121012022121002 |
4 | 200301123232323223302023 |
5 | 122342444444403024121 |
6 | 1230314252424005215 |
7 | 42234242541114602 |
oct | 4061335673536213 |
9 | 626303347168532 |
10 | 144134521142411 |
11 | 41a2011a673178 |
12 | 141ba29b60080b |
13 | 6256a99c7a847 |
14 | 2784210346a39 |
15 | 119e40a1c2e0b |
hex | 8316eeeebc8b |
144134521142411 has 2 divisors, whose sum is σ = 144134521142412. Its totient is φ = 144134521142410.
The previous prime is 144134521142383. The next prime is 144134521142453. The reversal of 144134521142411 is 114241125431441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144134521142411 - 26 = 144134521142347 is a prime.
It is a super-3 number, since 3×1441345211424113 (a number of 43 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (144134521142471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72067260571205 + 72067260571206.
It is an arithmetic number, because the mean of its divisors is an integer number (72067260571206).
Almost surely, 2144134521142411 is an apocalyptic number.
144134521142411 is a deficient number, since it is larger than the sum of its proper divisors (1).
144134521142411 is an equidigital number, since it uses as much as digits as its factorization.
144134521142411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 61440, while the sum is 38.
Adding to 144134521142411 its reverse (114241125431441), we get a palindrome (258375646573852).
The spelling of 144134521142411 in words is "one hundred forty-four trillion, one hundred thirty-four billion, five hundred twenty-one million, one hundred forty-two thousand, four hundred eleven".
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