114241125431441 has 4 divisors (see below), whose sum is σ = 114241194404352. Its totient is φ = 114241056458532.

The previous prime is 114241125431417. The next prime is 114241125431527. The reversal of 114241125431441 is 144134521142411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114241125431441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114241125431395 and 114241125431404.

It is not an unprimeable number, because it can be changed into a prime (114241125431141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31939265 + ... + 35335518.

It is an arithmetic number, because the mean of its divisors is an integer number (28560298601088).

Almost surely, 2^{114241125431441} is an apocalyptic number.

It is an amenable number.

114241125431441 is a deficient number, since it is larger than the sum of its proper divisors (68972911).

114241125431441 is an equidigital number, since it uses as much as digits as its factorization.

114241125431441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68972910.

The product of its digits is 61440, while the sum is 38.

Adding to 114241125431441 its reverse (144134521142411), we get a palindrome (258375646573852).

The spelling of 114241125431441 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred twenty-five million, four hundred thirty-one thousand, four hundred forty-one".