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144135314537581 is a prime number
BaseRepresentation
bin100000110001011100011110…
…001110001111110001101101
3200220100012102220002222011101
4200301130132032033301231
5122343003111010200311
61230314503245123101
742234301313632213
oct4061343616176155
9626305386088141
10144135314537581
1141a20497502764
12141ba481259491
136256b9545a343
142784287872cb3
15119e454b92ec1
hex83171e38fc6d

144135314537581 has 2 divisors, whose sum is σ = 144135314537582. Its totient is φ = 144135314537580.

The previous prime is 144135314537573. The next prime is 144135314537639. The reversal of 144135314537581 is 185735413531441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118672895776681 + 25462418760900 = 10893709^2 + 5046030^2 .

It is a cyclic number.

It is not a de Polignac number, because 144135314537581 - 23 = 144135314537573 is a prime.

It is a super-2 number, since 2×1441353145375812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144135314534581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72067657268790 + 72067657268791.

It is an arithmetic number, because the mean of its divisors is an integer number (72067657268791).

Almost surely, 2144135314537581 is an apocalyptic number.

It is an amenable number.

144135314537581 is a deficient number, since it is larger than the sum of its proper divisors (1).

144135314537581 is an equidigital number, since it uses as much as digits as its factorization.

144135314537581 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12096000, while the sum is 55.

The spelling of 144135314537581 in words is "one hundred forty-four trillion, one hundred thirty-five billion, three hundred fourteen million, five hundred thirty-seven thousand, five hundred eighty-one".