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144144521333 is a prime number
BaseRepresentation
bin1000011000111110101…
…1101101100001110101
3111210001200100101012022
42012033223231201311
54330201444140313
6150115153202525
713262015133611
oct2061753554165
9453050311168
10144144521333
115614990838a
1223b29860445
1310792414997
146d95c42341
153b399e2c08
hex218faed875

144144521333 has 2 divisors, whose sum is σ = 144144521334. Its totient is φ = 144144521332.

The previous prime is 144144521303. The next prime is 144144521357. The reversal of 144144521333 is 333125441441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117072096964 + 27072424369 = 342158^2 + 164537^2 .

It is a cyclic number.

It is not a de Polignac number, because 144144521333 - 210 = 144144520309 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 144144521293 and 144144521302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144144521303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72072260666 + 72072260667.

It is an arithmetic number, because the mean of its divisors is an integer number (72072260667).

Almost surely, 2144144521333 is an apocalyptic number.

It is an amenable number.

144144521333 is a deficient number, since it is larger than the sum of its proper divisors (1).

144144521333 is an equidigital number, since it uses as much as digits as its factorization.

144144521333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 35.

Adding to 144144521333 its reverse (333125441441), we get a palindrome (477269962774).

The spelling of 144144521333 in words is "one hundred forty-four billion, one hundred forty-four million, five hundred twenty-one thousand, three hundred thirty-three".