14415013545113 has 4 divisors (see below), whose sum is σ = 15173698468560. Its totient is φ = 13656328621668.

The previous prime is 14415013545077. The next prime is 14415013545157. The reversal of 14415013545113 is 31154531051441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14415013545113 - 2⁸ = 14415013544857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14415013545193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 379342461695 + ... + 379342461732.

It is an arithmetic number, because the mean of its divisors is an integer number (3793424617140).

Almost surely, 2^{14415013545113} is an apocalyptic number.

It is an amenable number.

14415013545113 is a deficient number, since it is larger than the sum of its proper divisors (758684923447).

14415013545113 is an equidigital number, since it uses as much as digits as its factorization.

14415013545113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 758684923446.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 14415013545113 its reverse (31154531051441), we get a palindrome (45569544596554).

The spelling of 14415013545113 in words is "fourteen trillion, four hundred fifteen billion, thirteen million, five hundred forty-five thousand, one hundred thirteen".