Base | Representation |
---|---|
bin | 10100111110111111000… |
… | …110100011110110100011 |
3 | 12002212002212102202000212 |
4 | 110332333012203312203 |
5 | 142111224133242011 |
6 | 3022242133404335 |
7 | 206116414364102 |
oct | 24767706436643 |
9 | 5085085382025 |
10 | 1442020212131 |
11 | 5066148a8634 |
12 | 1b35817996ab |
13 | a5c9c38c615 |
14 | 4db19214039 |
15 | 2779c19d08b |
hex | 14fbf1a3da3 |
1442020212131 has 2 divisors, whose sum is σ = 1442020212132. Its totient is φ = 1442020212130.
The previous prime is 1442020212121. The next prime is 1442020212151. The reversal of 1442020212131 is 1312120202441.
It is a weak prime.
It is an emirp because it is prime and its reverse (1312120202441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1442020212131 - 214 = 1442020195747 is a prime.
It is a super-2 number, since 2×14420202121312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1442020212097 and 1442020212106.
It is not a weakly prime, because it can be changed into another prime (1442020212121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721010106065 + 721010106066.
It is an arithmetic number, because the mean of its divisors is an integer number (721010106066).
Almost surely, 21442020212131 is an apocalyptic number.
1442020212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1442020212131 is an equidigital number, since it uses as much as digits as its factorization.
1442020212131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1442020212131 its reverse (1312120202441), we get a palindrome (2754140414572).
The spelling of 1442020212131 in words is "one trillion, four hundred forty-two billion, twenty million, two hundred twelve thousand, one hundred thirty-one".
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