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1442020212131 is a prime number
BaseRepresentation
bin10100111110111111000…
…110100011110110100011
312002212002212102202000212
4110332333012203312203
5142111224133242011
63022242133404335
7206116414364102
oct24767706436643
95085085382025
101442020212131
115066148a8634
121b35817996ab
13a5c9c38c615
144db19214039
152779c19d08b
hex14fbf1a3da3

1442020212131 has 2 divisors, whose sum is σ = 1442020212132. Its totient is φ = 1442020212130.

The previous prime is 1442020212121. The next prime is 1442020212151. The reversal of 1442020212131 is 1312120202441.

It is a weak prime.

It is an emirp because it is prime and its reverse (1312120202441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1442020212131 - 214 = 1442020195747 is a prime.

It is a super-2 number, since 2×14420202121312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1442020212097 and 1442020212106.

It is not a weakly prime, because it can be changed into another prime (1442020212121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721010106065 + 721010106066.

It is an arithmetic number, because the mean of its divisors is an integer number (721010106066).

Almost surely, 21442020212131 is an apocalyptic number.

1442020212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1442020212131 is an equidigital number, since it uses as much as digits as its factorization.

1442020212131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1442020212131 its reverse (1312120202441), we get a palindrome (2754140414572).

The spelling of 1442020212131 in words is "one trillion, four hundred forty-two billion, twenty million, two hundred twelve thousand, one hundred thirty-one".