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14420331324302 = 27210165662151
BaseRepresentation
bin1101000111010111111010…
…1110011110001110001110
31220001120101200110121111112
43101311332232132032032
53342230314304334202
650400335254052022
73015556152560411
oct321657656361616
956046350417445
1014420331324302
11465a6a0105942
12174a90b94a012
13807aa67b46a7
1437bd3a921b78
151a018c6acb52
hexd1d7eb9e38e

14420331324302 has 4 divisors (see below), whose sum is σ = 21630496986456. Its totient is φ = 7210165662150.

The previous prime is 14420331324283. The next prime is 14420331324331. The reversal of 14420331324302 is 20342313302441.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×144203313243024 (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3605082831074 + ... + 3605082831077.

It is an arithmetic number, because the mean of its divisors is an integer number (5407624246614).

Almost surely, 214420331324302 is an apocalyptic number.

14420331324302 is a deficient number, since it is larger than the sum of its proper divisors (7210165662154).

14420331324302 is an equidigital number, since it uses as much as digits as its factorization.

14420331324302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7210165662153.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 14420331324302 its reverse (20342313302441), we get a palindrome (34762644626743).

The spelling of 14420331324302 in words is "fourteen trillion, four hundred twenty billion, three hundred thirty-one million, three hundred twenty-four thousand, three hundred two".

Divisors: 1 2 7210165662151 14420331324302