Base | Representation |
---|---|
bin | 1101000111011011100100… |
… | …0111101100010010110011 |
3 | 1220001122220221221000012122 |
4 | 3101312321013230102303 |
5 | 3342234321104422232 |
6 | 50401020412144455 |
7 | 3015622350030656 |
oct | 321667107542263 |
9 | 56048827830178 |
10 | 14421311014067 |
11 | 4660053117301 |
12 | 174ab43a6812b |
13 | 807c01760189 |
14 | 37bdd0aa389d |
15 | 1a01e86cb312 |
hex | d1db91ec4b3 |
14421311014067 has 2 divisors, whose sum is σ = 14421311014068. Its totient is φ = 14421311014066.
The previous prime is 14421311014063. The next prime is 14421311014147. The reversal of 14421311014067 is 76041011312441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14421311014067 - 22 = 14421311014063 is a prime.
It is a super-2 number, since 2×144213110140672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14421311014063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210655507033 + 7210655507034.
It is an arithmetic number, because the mean of its divisors is an integer number (7210655507034).
Almost surely, 214421311014067 is an apocalyptic number.
14421311014067 is a deficient number, since it is larger than the sum of its proper divisors (1).
14421311014067 is an equidigital number, since it uses as much as digits as its factorization.
14421311014067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 14421311014067 in words is "fourteen trillion, four hundred twenty-one billion, three hundred eleven million, fourteen thousand, sixty-seven".
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