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144222413497 is a prime number
BaseRepresentation
bin1000011001010001010…
…0110110001010111001
3111210021002220201011021
42012110110312022321
54330331414212442
6150131014502441
713263652200511
oct2062424661271
9453232821137
10144222413497
1156189879978
1223b4b964a21
13107a55b7816
146da231a841
153b4177be67
hex21945362b9

144222413497 has 2 divisors, whose sum is σ = 144222413498. Its totient is φ = 144222413496.

The previous prime is 144222413371. The next prime is 144222413513. The reversal of 144222413497 is 794314222441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116261222841 + 27961190656 = 340971^2 + 167216^2 .

It is a cyclic number.

It is not a de Polignac number, because 144222413497 - 211 = 144222411449 is a prime.

It is a super-5 number, since 5×1442224134975 (a number of 57 digits) contains 55555 as substring.

It is not a weakly prime, because it can be changed into another prime (144222417497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72111206748 + 72111206749.

It is an arithmetic number, because the mean of its divisors is an integer number (72111206749).

Almost surely, 2144222413497 is an apocalyptic number.

It is an amenable number.

144222413497 is a deficient number, since it is larger than the sum of its proper divisors (1).

144222413497 is an equidigital number, since it uses as much as digits as its factorization.

144222413497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 387072, while the sum is 43.

The spelling of 144222413497 in words is "one hundred forty-four billion, two hundred twenty-two million, four hundred thirteen thousand, four hundred ninety-seven".