Base | Representation |
---|---|
bin | 1101000111011111101101… |
… | …1110001111011001110111 |
3 | 1220001202210112121210110021 |
4 | 3101313323132033121313 |
5 | 3342244111100040203 |
6 | 50401323100110011 |
7 | 3015662055112060 |
oct | 321677336173167 |
9 | 56052715553407 |
10 | 14422424221303 |
11 | 466057453238a |
12 | 174b1b4835307 |
13 | 80804b286497 |
14 | 37c09887d567 |
15 | 1a02612c05bd |
hex | d1dfb78f677 |
14422424221303 has 4 divisors (see below), whose sum is σ = 16482770538640. Its totient is φ = 12362077903968.
The previous prime is 14422424221291. The next prime is 14422424221313. The reversal of 14422424221303 is 30312242422441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14422424221303 - 233 = 14413834286711 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14422424221313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1030173158658 + ... + 1030173158671.
It is an arithmetic number, because the mean of its divisors is an integer number (4120692634660).
Almost surely, 214422424221303 is an apocalyptic number.
14422424221303 is a deficient number, since it is larger than the sum of its proper divisors (2060346317337).
14422424221303 is an equidigital number, since it uses as much as digits as its factorization.
14422424221303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2060346317336.
The product of its (nonzero) digits is 73728, while the sum is 34.
Adding to 14422424221303 its reverse (30312242422441), we get a palindrome (44734666643744).
The spelling of 14422424221303 in words is "fourteen trillion, four hundred twenty-two billion, four hundred twenty-four million, two hundred twenty-one thousand, three hundred three".
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