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14424101030113 is a prime number
BaseRepresentation
bin1101000111100101111101…
…1010110000100011100001
31220001221010101211111201021
43101321133122300203201
53342311024330430423
650402201320005441
73016051445544355
oct321713732604341
956057111744637
1014424101030113
114661254aa5695
12174b5a2300881
138082577a2c48
1437c1b7449465
151a030d5e295d
hexd1e5f6b08e1

14424101030113 has 2 divisors, whose sum is σ = 14424101030114. Its totient is φ = 14424101030112.

The previous prime is 14424101030069. The next prime is 14424101030117. The reversal of 14424101030113 is 31103010142441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11150871061264 + 3273229968849 = 3339292^2 + 1809207^2 .

It is a cyclic number.

It is not a de Polignac number, because 14424101030113 - 221 = 14424098932961 is a prime.

It is not a weakly prime, because it can be changed into another prime (14424101030117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7212050515056 + 7212050515057.

It is an arithmetic number, because the mean of its divisors is an integer number (7212050515057).

Almost surely, 214424101030113 is an apocalyptic number.

It is an amenable number.

14424101030113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14424101030113 is an equidigital number, since it uses as much as digits as its factorization.

14424101030113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14424101030113 its reverse (31103010142441), we get a palindrome (45527111172554).

The spelling of 14424101030113 in words is "fourteen trillion, four hundred twenty-four billion, one hundred one million, thirty thousand, one hundred thirteen".