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144252636433 is a prime number
BaseRepresentation
bin1000011001011000100…
…0001000110100010001
3111210100012210012020021
42012112020020310101
54330412133331213
6150134014343441
713264500115153
oct2062610106421
9453305705207
10144252636433
11561a4941904
1223b59abab81
13107ab93a109
146da6346ad3
153b4424bd8d
hex2196208d11

144252636433 has 2 divisors, whose sum is σ = 144252636434. Its totient is φ = 144252636432.

The previous prime is 144252636373. The next prime is 144252636461. The reversal of 144252636433 is 334636252441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144120455424 + 132181009 = 379632^2 + 11497^2 .

It is a cyclic number.

It is not a de Polignac number, because 144252636433 - 213 = 144252628241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 144252636433.

It is not a weakly prime, because it can be changed into another prime (144252636233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72126318216 + 72126318217.

It is an arithmetic number, because the mean of its divisors is an integer number (72126318217).

Almost surely, 2144252636433 is an apocalyptic number.

It is an amenable number.

144252636433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144252636433 is an equidigital number, since it uses as much as digits as its factorization.

144252636433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1244160, while the sum is 43.

Adding to 144252636433 its reverse (334636252441), we get a palindrome (478888888874).

The spelling of 144252636433 in words is "one hundred forty-four billion, two hundred fifty-two million, six hundred thirty-six thousand, four hundred thirty-three".