Base | Representation |
---|---|
bin | 10100111111100101011… |
… | …111010001011010010001 |
3 | 12002220202202020221210011 |
4 | 110333211133101122101 |
5 | 142114034020140101 |
6 | 3022430101034521 |
7 | 206141364401641 |
oct | 24774537213221 |
9 | 5086682227704 |
10 | 1442664224401 |
11 | 506915387584 |
12 | 1b37213b5a41 |
13 | a607292807a |
14 | 4db7a976521 |
15 | 277d89b1751 |
hex | 14fe57d1691 |
1442664224401 has 2 divisors, whose sum is σ = 1442664224402. Its totient is φ = 1442664224400.
The previous prime is 1442664224303. The next prime is 1442664224411. The reversal of 1442664224401 is 1044224662441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1111440954001 + 331223270400 = 1054249^2 + 575520^2 .
It is a cyclic number.
It is not a de Polignac number, because 1442664224401 - 213 = 1442664216209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1442664224411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721332112200 + 721332112201.
It is an arithmetic number, because the mean of its divisors is an integer number (721332112201).
Almost surely, 21442664224401 is an apocalyptic number.
It is an amenable number.
1442664224401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1442664224401 is an equidigital number, since it uses as much as digits as its factorization.
1442664224401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 294912, while the sum is 40.
Adding to 1442664224401 its reverse (1044224662441), we get a palindrome (2486888886842).
The spelling of 1442664224401 in words is "one trillion, four hundred forty-two billion, six hundred sixty-four million, two hundred twenty-four thousand, four hundred one".
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