Base | Representation |
---|---|
bin | 11010111000010011… |
… | …11001011000110010 |
3 | 1101020201110202120201 |
4 | 31130021321120302 |
5 | 214023314000424 |
6 | 10343550225414 |
7 | 1020420322426 |
oct | 153411713062 |
9 | 41221422521 |
10 | 14431000114 |
11 | 6135a17a83 |
12 | 2968ab526a |
13 | 148c9b572b |
14 | 9ac82ab86 |
15 | 596dbbd44 |
hex | 35c279632 |
14431000114 has 4 divisors (see below), whose sum is σ = 21646500174. Its totient is φ = 7215500056.
The previous prime is 14431000081. The next prime is 14431000151. The reversal of 14431000114 is 41100013441.
14431000114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13475262889 + 955737225 = 116083^2 + 30915^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14431000091 and 14431000100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3607750027 + ... + 3607750030.
Almost surely, 214431000114 is an apocalyptic number.
14431000114 is a deficient number, since it is larger than the sum of its proper divisors (7215500060).
14431000114 is an equidigital number, since it uses as much as digits as its factorization.
14431000114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7215500059.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 14431000114 its reverse (41100013441), we get a palindrome (55531013555).
The spelling of 14431000114 in words is "fourteen billion, four hundred thirty-one million, one hundred fourteen", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •