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14431023412131 = 38675895544493
BaseRepresentation
bin1101000111111111110000…
…0001100011001110100011
31220002120222211111221122110
43101333330001203032203
53342414213443142011
650405304242410403
73016415133041214
oct321777401431643
956076884457573
1014431023412131
114664187555767
1217509b4660a03
13808abb9a0a91
1437c67295d40b
151a05b61c8ba6
hexd1ffc0633a3

14431023412131 has 8 divisors (see below), whose sum is σ = 19241390197840. Its totient is φ = 9620669450592.

The previous prime is 14431023412123. The next prime is 14431023412151. The reversal of 14431023412131 is 13121432013441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14431023412131 - 23 = 14431023412123 is a prime.

It is a super-2 number, since 2×144310234121312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14431023412151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 169480 + ... + 5375013.

It is an arithmetic number, because the mean of its divisors is an integer number (2405173774730).

Almost surely, 214431023412131 is an apocalyptic number.

14431023412131 is a deficient number, since it is larger than the sum of its proper divisors (4810366785709).

14431023412131 is an equidigital number, since it uses as much as digits as its factorization.

14431023412131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6412085.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 14431023412131 its reverse (13121432013441), we get a palindrome (27552455425572).

The spelling of 14431023412131 in words is "fourteen trillion, four hundred thirty-one billion, twenty-three million, four hundred twelve thousand, one hundred thirty-one".

Divisors: 1 3 867589 2602767 5544493 16633479 4810341137377 14431023412131