144311024000113 has 12 divisors (see below), whose sum is σ = 154935465117748. Its totient is φ = 134305911859680.

The previous prime is 144311024000063. The next prime is 144311024000147. The reversal of 144311024000113 is 311000420113441.

It can be written as a sum of positive squares in 2 ways, for example, as 130008158060544 + 14302865939569 = 11402112^2 + 3781913^2 .

It is not a de Polignac number, because 144311024000113 - 2³³ = 144302434065521 is a prime.

It is a super-2 number, since 2×144311024000113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144311024000513) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3686462418 + ... + 3686501563.

Almost surely, 2^{144311024000113} is an apocalyptic number.

It is an amenable number.

144311024000113 is a deficient number, since it is larger than the sum of its proper divisors (10624441117635).

144311024000113 is an equidigital number, since it uses as much as digits as its factorization.

144311024000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7372964064 (or 7372964041 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 144311024000113 its reverse (311000420113441), we get a palindrome (455311444113554).

The spelling of 144311024000113 in words is "one hundred forty-four trillion, three hundred eleven billion, twenty-four million, one hundred thirteen", and thus it is an aban number.