Base | Representation |
---|---|
bin | 100000110100000000011001… |
… | …101111110100111000111011 |
3 | 200220222000202221010002012022 |
4 | 200310000121233310320323 |
5 | 122403344102234112103 |
6 | 1230531413342105055 |
7 | 42253102236063521 |
oct | 4064003157647073 |
9 | 626860687102168 |
10 | 144311333113403 |
11 | 41a89102398a35 |
12 | 1422860557b18b |
13 | 626a6672852a1 |
14 | 278c9c4992311 |
15 | 11a3d07a95138 |
hex | 834019bf4e3b |
144311333113403 has 2 divisors, whose sum is σ = 144311333113404. Its totient is φ = 144311333113402.
The previous prime is 144311333113327. The next prime is 144311333113499. The reversal of 144311333113403 is 304311333113441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144311333113403 - 28 = 144311333113147 is a prime.
It is not a weakly prime, because it can be changed into another prime (144311333115403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72155666556701 + 72155666556702.
It is an arithmetic number, because the mean of its divisors is an integer number (72155666556702).
Almost surely, 2144311333113403 is an apocalyptic number.
144311333113403 is a deficient number, since it is larger than the sum of its proper divisors (1).
144311333113403 is an equidigital number, since it uses as much as digits as its factorization.
144311333113403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 35.
Adding to 144311333113403 its reverse (304311333113441), we get a palindrome (448622666226844).
The spelling of 144311333113403 in words is "one hundred forty-four trillion, three hundred eleven billion, three hundred thirty-three million, one hundred thirteen thousand, four hundred three".
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