1443122213441 has 4 divisors (see below), whose sum is σ = 1443166247892. Its totient is φ = 1443078178992.

The previous prime is 1443122213431. The next prime is 1443122213461.

1443122213441 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 991410524416 + 451711689025 = 995696^2 + 672095^2 .

It is a cyclic number.

It is not a de Polignac number, because 1443122213441 - 2²⁶ = 1443055104577 is a prime.

It is a super-2 number, since 2×1443122213441² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1443122213398 and 1443122213407.

It is not an unprimeable number, because it can be changed into a prime (1443122213411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21968030 + ... + 22033623.

It is an arithmetic number, because the mean of its divisors is an integer number (360791561973).

Almost surely, 2^{1443122213441} is an apocalyptic number.

It is an amenable number.

1443122213441 is a deficient number, since it is larger than the sum of its proper divisors (44034451).

1443122213441 is an equidigital number, since it uses as much as digits as its factorization.

1443122213441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44034450.

The product of its digits is 18432, while the sum is 32.

The spelling of 1443122213441 in words is "one trillion, four hundred forty-three billion, one hundred twenty-two million, two hundred thirteen thousand, four hundred forty-one".