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144313004201 = 1399103154399
BaseRepresentation
bin1000011001100110111…
…0011011000010101001
3111210111102101012020112
42012121232123002221
54331023112113301
6150144012304105
713266132203402
oct2063156330251
9453442335215
10144313004201
1156225a24023
1223b76172035
13107bb2b55a2
146db037c9a9
153b496c39bb
hex2199b9b0a9

144313004201 has 4 divisors (see below), whose sum is σ = 144416160000. Its totient is φ = 144209848404.

The previous prime is 144313004153. The next prime is 144313004219. The reversal of 144313004201 is 102400313441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144313004201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144313054201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51575801 + ... + 51578598.

It is an arithmetic number, because the mean of its divisors is an integer number (36104040000).

Almost surely, 2144313004201 is an apocalyptic number.

It is an amenable number.

144313004201 is a deficient number, since it is larger than the sum of its proper divisors (103155799).

144313004201 is a wasteful number, since it uses less digits than its factorization.

144313004201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103155798.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 144313004201 its reverse (102400313441), we get a palindrome (246713317642).

The spelling of 144313004201 in words is "one hundred forty-four billion, three hundred thirteen million, four thousand, two hundred one".

Divisors: 1 1399 103154399 144313004201