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1443131132017 is a prime number
BaseRepresentation
bin10101000000000001010…
…100011000100001110001
312002221222021211022121211
4111000001110120201301
5142121013032211032
63022544300320121
7206156064140431
oct25000124304161
95087867738554
101443131132017
115070349a1143
121b3831843041
13a6118594773
144dbc29962c1
152781498e747
hex15001518871

1443131132017 has 2 divisors, whose sum is σ = 1443131132018. Its totient is φ = 1443131132016.

The previous prime is 1443131131927. The next prime is 1443131132077. The reversal of 1443131132017 is 7102311313441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1010425029601 + 432706102416 = 1005199^2 + 657804^2 .

It is a cyclic number.

It is not a de Polignac number, because 1443131132017 - 219 = 1443130607729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1443131132017.

It is not a weakly prime, because it can be changed into another prime (1443131132077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721565566008 + 721565566009.

It is an arithmetic number, because the mean of its divisors is an integer number (721565566009).

Almost surely, 21443131132017 is an apocalyptic number.

It is an amenable number.

1443131132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1443131132017 is an equidigital number, since it uses as much as digits as its factorization.

1443131132017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1443131132017 its reverse (7102311313441), we get a palindrome (8545442445458).

The spelling of 1443131132017 in words is "one trillion, four hundred forty-three billion, one hundred thirty-one million, one hundred thirty-two thousand, seventeen".