Base | Representation |
---|---|
bin | 11010111000010110… |
… | …11111111011111001 |
3 | 1101020202021002202201 |
4 | 31130023133323321 |
5 | 214023420421103 |
6 | 10344003230201 |
7 | 1020424022143 |
oct | 153413377371 |
9 | 41222232681 |
10 | 14431420153 |
11 | 6136184617 |
12 | 2969078361 |
13 | 148cb01987 |
14 | 9ac8d9c93 |
15 | 596e5151d |
hex | 35c2dfef9 |
14431420153 has 2 divisors, whose sum is σ = 14431420154. Its totient is φ = 14431420152.
The previous prime is 14431420123. The next prime is 14431420163. The reversal of 14431420153 is 35102413441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14114152809 + 317267344 = 118803^2 + 17812^2 .
It is a cyclic number.
It is not a de Polignac number, because 14431420153 - 213 = 14431411961 is a prime.
It is not a weakly prime, because it can be changed into another prime (14431420123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7215710076 + 7215710077.
It is an arithmetic number, because the mean of its divisors is an integer number (7215710077).
Almost surely, 214431420153 is an apocalyptic number.
It is an amenable number.
14431420153 is a deficient number, since it is larger than the sum of its proper divisors (1).
14431420153 is an equidigital number, since it uses as much as digits as its factorization.
14431420153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14431420153 its reverse (35102413441), we get a palindrome (49533833594).
The spelling of 14431420153 in words is "fourteen billion, four hundred thirty-one million, four hundred twenty thousand, one hundred fifty-three".
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