1443144402131 has 2 divisors, whose sum is σ = 1443144402132. Its totient is φ = 1443144402130.

The previous prime is 1443144402121. The next prime is 1443144402253. The reversal of 1443144402131 is 1312044413441.

It is a weak prime.

It is an emirp because it is prime and its reverse (1312044413441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1443144402131 - 2¹⁴ = 1443144385747 is a prime.

It is a super-2 number, since 2×1443144402131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1443144402121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721572201065 + 721572201066.

It is an arithmetic number, because the mean of its divisors is an integer number (721572201066).

Almost surely, 2^{1443144402131} is an apocalyptic number.

1443144402131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1443144402131 is an equidigital number, since it uses as much as digits as its factorization.

1443144402131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 1443144402131 its reverse (1312044413441), we get a palindrome (2755188815572).

The spelling of 1443144402131 in words is "one trillion, four hundred forty-three billion, one hundred forty-four million, four hundred two thousand, one hundred thirty-one".