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14432575403 is a prime number
BaseRepresentation
bin11010111000011111…
…11001111110101011
31101020211102210110202
431130033321332223
5214024214403103
610344044102415
71020436603211
oct153417717653
941224383422
1014432575403
1161368a3574
122969534a0b
13149011775c
149acb1acb1
155970cd988
hex35c3f9fab

14432575403 has 2 divisors, whose sum is σ = 14432575404. Its totient is φ = 14432575402.

The previous prime is 14432575397. The next prime is 14432575447. The reversal of 14432575403 is 30457523441.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14432575403 is a prime.

It is a super-2 number, since 2×144325754032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14432575603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216287701 + 7216287702.

It is an arithmetic number, because the mean of its divisors is an integer number (7216287702).

Almost surely, 214432575403 is an apocalyptic number.

14432575403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14432575403 is an equidigital number, since it uses as much as digits as its factorization.

14432575403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 38.

The spelling of 14432575403 in words is "fourteen billion, four hundred thirty-two million, five hundred seventy-five thousand, four hundred three".