Base | Representation |
---|---|
bin | 11010111000100100… |
… | …00001101101001101 |
3 | 1101020212111001002001 |
4 | 31130102001231031 |
5 | 214024340200331 |
6 | 10344104032301 |
7 | 1020444410056 |
oct | 153422015515 |
9 | 41225431061 |
10 | 14433131341 |
11 | 6137143222 |
12 | 2969762691 |
13 | 1490280805 |
14 | 9acc2372d |
15 | 59718d561 |
hex | 35c481b4d |
14433131341 has 4 divisors (see below), whose sum is σ = 14565545500. Its totient is φ = 14300717184.
The previous prime is 14433131333. The next prime is 14433131387. The reversal of 14433131341 is 14313133441.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7486575625 + 6946555716 = 86525^2 + 83346^2 .
It is a cyclic number.
It is not a de Polignac number, because 14433131341 - 23 = 14433131333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14433161341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66206916 + ... + 66207133.
It is an arithmetic number, because the mean of its divisors is an integer number (3641386375).
Almost surely, 214433131341 is an apocalyptic number.
It is an amenable number.
14433131341 is a deficient number, since it is larger than the sum of its proper divisors (132414159).
14433131341 is a wasteful number, since it uses less digits than its factorization.
14433131341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132414158.
The product of its digits is 5184, while the sum is 28.
Adding to 14433131341 its reverse (14313133441), we get a palindrome (28746264782).
The spelling of 14433131341 in words is "fourteen billion, four hundred thirty-three million, one hundred thirty-one thousand, three hundred forty-one".
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