Base | Representation |
---|---|
bin | 11010111000100100… |
… | …11100100000011101 |
3 | 1101020212200121122211 |
4 | 31130102130200131 |
5 | 214024402203432 |
6 | 10344110240421 |
7 | 1020445345111 |
oct | 153422344035 |
9 | 41225617584 |
10 | 14433241117 |
11 | 6137208749 |
12 | 29697b6111 |
13 | 14902bb779 |
14 | 9acc51741 |
15 | 5971b0d47 |
hex | 35c49c81d |
14433241117 has 2 divisors, whose sum is σ = 14433241118. Its totient is φ = 14433241116.
The previous prime is 14433240979. The next prime is 14433241127. The reversal of 14433241117 is 71114233441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10183635396 + 4249605721 = 100914^2 + 65189^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14433241117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14433241127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216620558 + 7216620559.
It is an arithmetic number, because the mean of its divisors is an integer number (7216620559).
Almost surely, 214433241117 is an apocalyptic number.
It is an amenable number.
14433241117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14433241117 is an equidigital number, since it uses as much as digits as its factorization.
14433241117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8064, while the sum is 31.
Adding to 14433241117 its reverse (71114233441), we get a palindrome (85547474558).
It can be divided in two parts, 1443324 and 1117, that added together give a palindrome (1444441).
The spelling of 14433241117 in words is "fourteen billion, four hundred thirty-three million, two hundred forty-one thousand, one hundred seventeen".
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