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14434113 = 34811371
BaseRepresentation
bin110111000011…
…111101000001
31000011022212210
4313003331001
512143342423
61233212333
7233454651
oct67037501
930138783
1014434113
118169621
124a010a9
132cb4bc5
141cba361
151401b93
hexdc3f41

14434113 has 4 divisors (see below), whose sum is σ = 19245488. Its totient is φ = 9622740.

The previous prime is 14434097. The next prime is 14434163. The reversal of 14434113 is 31143441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14434113 - 24 = 14434097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14434113.

It is not an unprimeable number, because it can be changed into a prime (14434163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2405683 + ... + 2405688.

It is an arithmetic number, because the mean of its divisors is an integer number (4811372).

Almost surely, 214434113 is an apocalyptic number.

It is an amenable number.

14434113 is a deficient number, since it is larger than the sum of its proper divisors (4811375).

14434113 is an equidigital number, since it uses as much as digits as its factorization.

14434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4811374.

The product of its digits is 576, while the sum is 21.

The square root of 14434113 is about 3799.2253157716. The cubic root of 14434113 is about 243.4800414277.

Adding to 14434113 its reverse (31143441), we get a palindrome (45577554).

The spelling of 14434113 in words is "fourteen million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 4811371 14434113