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14434320430403 is a prime number
BaseRepresentation
bin1101001000001100000010…
…0010101011010101000011
31220002220111121102211110022
43102003000202223111003
53342442442012233103
650411011341124055
73016562626164326
oct322030042532503
956086447384408
1014434320430403
114665619643355
12175157485962b
138091c5a7ab73
1437c8a67a07bd
151a070a88d138
hexd20c08ab543

14434320430403 has 2 divisors, whose sum is σ = 14434320430404. Its totient is φ = 14434320430402.

The previous prime is 14434320430399. The next prime is 14434320430417. The reversal of 14434320430403 is 30403402343441.

It is a weak prime.

It is an emirp because it is prime and its reverse (30403402343441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14434320430403 - 22 = 14434320430399 is a prime.

It is not a weakly prime, because it can be changed into another prime (14434320430423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217160215201 + 7217160215202.

It is an arithmetic number, because the mean of its divisors is an integer number (7217160215202).

Almost surely, 214434320430403 is an apocalyptic number.

14434320430403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434320430403 is an equidigital number, since it uses as much as digits as its factorization.

14434320430403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 14434320430403 its reverse (30403402343441), we get a palindrome (44837722773844).

The spelling of 14434320430403 in words is "fourteen trillion, four hundred thirty-four billion, three hundred twenty million, four hundred thirty thousand, four hundred three".