Base | Representation |
---|---|
bin | 1101001000001100000010… |
… | …0010101011010101000011 |
3 | 1220002220111121102211110022 |
4 | 3102003000202223111003 |
5 | 3342442442012233103 |
6 | 50411011341124055 |
7 | 3016562626164326 |
oct | 322030042532503 |
9 | 56086447384408 |
10 | 14434320430403 |
11 | 4665619643355 |
12 | 175157485962b |
13 | 8091c5a7ab73 |
14 | 37c8a67a07bd |
15 | 1a070a88d138 |
hex | d20c08ab543 |
14434320430403 has 2 divisors, whose sum is σ = 14434320430404. Its totient is φ = 14434320430402.
The previous prime is 14434320430399. The next prime is 14434320430417. The reversal of 14434320430403 is 30403402343441.
It is a weak prime.
It is an emirp because it is prime and its reverse (30403402343441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14434320430403 - 22 = 14434320430399 is a prime.
It is not a weakly prime, because it can be changed into another prime (14434320430423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217160215201 + 7217160215202.
It is an arithmetic number, because the mean of its divisors is an integer number (7217160215202).
Almost surely, 214434320430403 is an apocalyptic number.
14434320430403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14434320430403 is an equidigital number, since it uses as much as digits as its factorization.
14434320430403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 14434320430403 its reverse (30403402343441), we get a palindrome (44837722773844).
The spelling of 14434320430403 in words is "fourteen trillion, four hundred thirty-four billion, three hundred twenty million, four hundred thirty thousand, four hundred three".
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