Base | Representation |
---|---|
bin | 1101001000001100000011… |
… | …0000110011101010010011 |
3 | 1220002220111212102000120211 |
4 | 3102003000300303222103 |
5 | 3342442443434301142 |
6 | 50411011552344551 |
7 | 3016563002522512 |
oct | 322030060635223 |
9 | 56086455360524 |
10 | 14434324134547 |
11 | 4665620743329 |
12 | 1751575b45157 |
13 | 8091c6776b75 |
14 | 37c8a7086679 |
15 | 1a070ad70917 |
hex | d20c0c33a93 |
14434324134547 has 2 divisors, whose sum is σ = 14434324134548. Its totient is φ = 14434324134546.
The previous prime is 14434324134421. The next prime is 14434324134557. The reversal of 14434324134547 is 74543142343441.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (74543142343441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14434324134547 - 223 = 14434315745939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14434324134547.
It is not a weakly prime, because it can be changed into another prime (14434324134557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217162067273 + 7217162067274.
It is an arithmetic number, because the mean of its divisors is an integer number (7217162067274).
Almost surely, 214434324134547 is an apocalyptic number.
14434324134547 is a deficient number, since it is larger than the sum of its proper divisors (1).
14434324134547 is an equidigital number, since it uses as much as digits as its factorization.
14434324134547 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7741440, while the sum is 49.
Adding to 14434324134547 its reverse (74543142343441), we get a palindrome (88977466477988).
The spelling of 14434324134547 in words is "fourteen trillion, four hundred thirty-four billion, three hundred twenty-four million, one hundred thirty-four thousand, five hundred forty-seven".
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