14434331421203 has 4 divisors (see below), whose sum is σ = 14497918784520. Its totient is φ = 14370744057888.

The previous prime is 14434331421199. The next prime is 14434331421233. The reversal of 14434331421203 is 30212413343441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14434331421203 - 2² = 14434331421199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14434331421233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31793681318 + ... + 31793681771.

It is an arithmetic number, because the mean of its divisors is an integer number (3624479696130).

Almost surely, 2^{14434331421203} is an apocalyptic number.

14434331421203 is a deficient number, since it is larger than the sum of its proper divisors (63587363317).

14434331421203 is an equidigital number, since it uses as much as digits as its factorization.

14434331421203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63587363316.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 14434331421203 its reverse (30212413343441), we get a palindrome (44646744764644).

The spelling of 14434331421203 in words is "fourteen trillion, four hundred thirty-four billion, three hundred thirty-one million, four hundred twenty-one thousand, two hundred three".