Base | Representation |
---|---|
bin | 1101001000001100011100… |
… | …1000111101111010100101 |
3 | 1220002220210022202000112120 |
4 | 3102003013020331322211 |
5 | 3342443203332200201 |
6 | 50411030333540153 |
7 | 3016565442135426 |
oct | 322030710757245 |
9 | 56086708660476 |
10 | 14434431131301 |
11 | 46656760835a5 |
12 | 17515a5944659 |
13 | 80921299a25c |
14 | 37c8b737964d |
15 | 1a0715458536 |
hex | d20c723dea5 |
14434431131301 has 4 divisors (see below), whose sum is σ = 19245908175072. Its totient is φ = 9622954087532.
The previous prime is 14434431131291. The next prime is 14434431131311. The reversal of 14434431131301 is 10313113443441.
14434431131301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (14434431131291) and next prime (14434431131311).
It is a cyclic number.
It is not a de Polignac number, because 14434431131301 - 29 = 14434431130789 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14434431131311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2405738521881 + ... + 2405738521886.
It is an arithmetic number, because the mean of its divisors is an integer number (4811477043768).
Almost surely, 214434431131301 is an apocalyptic number.
It is an amenable number.
14434431131301 is a deficient number, since it is larger than the sum of its proper divisors (4811477043771).
14434431131301 is an equidigital number, since it uses as much as digits as its factorization.
14434431131301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4811477043770.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 14434431131301 its reverse (10313113443441), we get a palindrome (24747544574742).
The spelling of 14434431131301 in words is "fourteen trillion, four hundred thirty-four billion, four hundred thirty-one million, one hundred thirty-one thousand, three hundred one".
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