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144350554433 is a prime number
BaseRepresentation
bin1000011001101111110…
…1101010100101000001
3111210121001000221110212
42012123331222211001
54331112220220213
6150151433203505
713300066316321
oct2063375524501
9453531027425
10144350554433
1156245141078
1223b86860595
13107c6002067
146db5355281
153b4cb3e9a8
hex219bf6a941

144350554433 has 2 divisors, whose sum is σ = 144350554434. Its totient is φ = 144350554432.

The previous prime is 144350554393. The next prime is 144350554459. The reversal of 144350554433 is 334455053441.

It is a happy number.

144350554433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141595669264 + 2754885169 = 376292^2 + 52487^2 .

It is a cyclic number.

It is not a de Polignac number, because 144350554433 - 28 = 144350554177 is a prime.

It is a super-2 number, since 2×1443505544332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144350554493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72175277216 + 72175277217.

It is an arithmetic number, because the mean of its divisors is an integer number (72175277217).

Almost surely, 2144350554433 is an apocalyptic number.

It is an amenable number.

144350554433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144350554433 is an equidigital number, since it uses as much as digits as its factorization.

144350554433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864000, while the sum is 41.

The spelling of 144350554433 in words is "one hundred forty-four billion, three hundred fifty million, five hundred fifty-four thousand, four hundred thirty-three".