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14435404117 is a prime number
BaseRepresentation
bin11010111000110101…
…01100100101010101
31101021000202111201221
431130122230211111
5214030430412432
610344224450341
71020502624201
oct153432544525
941230674657
1014435404117
116138455852
12296a4799b1
131490898154
149ad255b01
1559748bb97
hex35c6ac955

14435404117 has 2 divisors, whose sum is σ = 14435404118. Its totient is φ = 14435404116.

The previous prime is 14435404057. The next prime is 14435404171. The reversal of 14435404117 is 71140453441.

Together with next prime (14435404171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8592177636 + 5843226481 = 92694^2 + 76441^2 .

It is a cyclic number.

It is not a de Polignac number, because 14435404117 - 223 = 14427015509 is a prime.

It is a super-2 number, since 2×144354041172 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14435404817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217702058 + 7217702059.

It is an arithmetic number, because the mean of its divisors is an integer number (7217702059).

Almost surely, 214435404117 is an apocalyptic number.

It is an amenable number.

14435404117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14435404117 is an equidigital number, since it uses as much as digits as its factorization.

14435404117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 34.

Adding to 14435404117 its reverse (71140453441), we get a palindrome (85575857558).

The spelling of 14435404117 in words is "fourteen billion, four hundred thirty-five million, four hundred four thousand, one hundred seventeen".