Base | Representation |
---|---|
bin | 11010111001010010… |
… | …10101000100011011 |
3 | 1101021021222101112022 |
4 | 31130221111010123 |
5 | 214032421134323 |
6 | 10344443005055 |
7 | 1020550341341 |
oct | 153451250433 |
9 | 41237871468 |
10 | 14439239963 |
11 | 613a635775 |
12 | 296b80978b |
13 | 149160c095 |
14 | 9ad973991 |
15 | 5979984c8 |
hex | 35ca5511b |
14439239963 has 2 divisors, whose sum is σ = 14439239964. Its totient is φ = 14439239962.
The previous prime is 14439239953. The next prime is 14439240007. The reversal of 14439239963 is 36993293441.
14439239963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14439239963 - 220 = 14438191387 is a prime.
It is not a weakly prime, because it can be changed into another prime (14439239953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7219619981 + 7219619982.
It is an arithmetic number, because the mean of its divisors is an integer number (7219619982).
Almost surely, 214439239963 is an apocalyptic number.
14439239963 is a deficient number, since it is larger than the sum of its proper divisors (1).
14439239963 is an equidigital number, since it uses as much as digits as its factorization.
14439239963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3779136, while the sum is 53.
The spelling of 14439239963 in words is "fourteen billion, four hundred thirty-nine million, two hundred thirty-nine thousand, nine hundred sixty-three".
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