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14440121 is a prime number
BaseRepresentation
bin110111000101…
…011010111001
31000011122010022
4313011122321
512144040441
61233300225
7233511323
oct67053271
930148108
1014440121
118173093
124a04675
132cb7867
141cbc613
15140384b
hexdc56b9

14440121 has 2 divisors, whose sum is σ = 14440122. Its totient is φ = 14440120.

The previous prime is 14440061. The next prime is 14440147. The reversal of 14440121 is 12104441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14440000 + 121 = 3800^2 + 11^2 .

It is an emirp because it is prime and its reverse (12104441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14440121 - 210 = 14439097 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14440121.

It is not a weakly prime, because it can be changed into another prime (14442121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220060 + 7220061.

It is an arithmetic number, because the mean of its divisors is an integer number (7220061).

Almost surely, 214440121 is an apocalyptic number.

It is an amenable number.

14440121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14440121 is an equidigital number, since it uses as much as digits as its factorization.

14440121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 14440121 is about 3800.0159210193. The cubic root of 14440121 is about 243.5138184755.

Adding to 14440121 its reverse (12104441), we get a palindrome (26544562).

The spelling of 14440121 in words is "fourteen million, four hundred forty thousand, one hundred twenty-one".