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144403112134 = 272201556067
BaseRepresentation
bin1000011001111100011…
…0001010000011000110
3111210201200221011002101
42012133012022003012
54331214144042014
6150200551502314
713301305125631
oct2063706120306
9453650834071
10144403112134
1156271879496
1223ba038799a
1310803b746a8
146dbc316c18
153b52572474
hex219f18a0c6

144403112134 has 4 divisors (see below), whose sum is σ = 216604668204. Its totient is φ = 72201556066.

The previous prime is 144403112101. The next prime is 144403112137. The reversal of 144403112134 is 431211304441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 431211304441 = 1109388828949.

It is a super-3 number, since 3×1444031121343 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144403112137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36100778032 + ... + 36100778035.

It is an arithmetic number, because the mean of its divisors is an integer number (54151167051).

Almost surely, 2144403112134 is an apocalyptic number.

144403112134 is a deficient number, since it is larger than the sum of its proper divisors (72201556070).

144403112134 is an equidigital number, since it uses as much as digits as its factorization.

144403112134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72201556069.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 144403112134 its reverse (431211304441), we get a palindrome (575614416575).

The spelling of 144403112134 in words is "one hundred forty-four billion, four hundred three million, one hundred twelve thousand, one hundred thirty-four".

Divisors: 1 2 72201556067 144403112134