Base | Representation |
---|---|
bin | 1101001000100010011100… |
… | …0000001110110100111111 |
3 | 1220010111000201211020001022 |
4 | 3102020213000032310333 |
5 | 3343042301102440221 |
6 | 50413444213534355 |
7 | 3020164643233451 |
oct | 322104700166477 |
9 | 56114021736038 |
10 | 14440334421311 |
11 | 466812535a777 |
12 | 17527729443bb |
13 | 809943a04b76 |
14 | 37ccb73b22d1 |
15 | 1a095d83b4ab |
hex | d222700ed3f |
14440334421311 has 2 divisors, whose sum is σ = 14440334421312. Its totient is φ = 14440334421310.
The previous prime is 14440334421257. The next prime is 14440334421361. The reversal of 14440334421311 is 11312443304441.
It is a strong prime.
It is an emirp because it is prime and its reverse (11312443304441) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14440334421311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14440334421361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220167210655 + 7220167210656.
It is an arithmetic number, because the mean of its divisors is an integer number (7220167210656).
Almost surely, 214440334421311 is an apocalyptic number.
14440334421311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14440334421311 is an equidigital number, since it uses as much as digits as its factorization.
14440334421311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 14440334421311 its reverse (11312443304441), we get a palindrome (25752777725752).
The spelling of 14440334421311 in words is "fourteen trillion, four hundred forty billion, three hundred thirty-four million, four hundred twenty-one thousand, three hundred eleven".
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