Base | Representation |
---|---|
bin | 100000110101011000000000… |
… | …101000110110100011001111 |
3 | 200221022000120200200201021201 |
4 | 200311120000220312203033 |
5 | 122411414230142312221 |
6 | 1231042531522210331 |
7 | 42262642313061331 |
oct | 4065300050664317 |
9 | 627260520621251 |
10 | 144405401135311 |
11 | 42014a943330a8 |
12 | 142428987b39a7 |
13 | 62764a8b24304 |
14 | 2793389c6d451 |
15 | 11a64b1131891 |
hex | 835600a368cf |
144405401135311 has 4 divisors (see below), whose sum is σ = 144405435718800. Its totient is φ = 144405366551824.
The previous prime is 144405401135309. The next prime is 144405401135327. The reversal of 144405401135311 is 113531104504441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144405401135311 - 21 = 144405401135309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144405401735311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10004806 + ... + 19720723.
It is an arithmetic number, because the mean of its divisors is an integer number (36101358929700).
Almost surely, 2144405401135311 is an apocalyptic number.
144405401135311 is a deficient number, since it is larger than the sum of its proper divisors (34583489).
144405401135311 is an equidigital number, since it uses as much as digits as its factorization.
144405401135311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34583488.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 144405401135311 its reverse (113531104504441), we get a palindrome (257936505639752).
The spelling of 144405401135311 in words is "one hundred forty-four trillion, four hundred five billion, four hundred one million, one hundred thirty-five thousand, three hundred eleven".
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