Base | Representation |
---|---|
bin | 1101001000100101011001… |
… | …1111101111011000000010 |
3 | 1220010120002021010021222110 |
4 | 3102021112133233120002 |
5 | 3343100414042211432 |
6 | 50414055235520150 |
7 | 3020223456644322 |
oct | 322112637573002 |
9 | 56116067107873 |
10 | 14441131210242 |
11 | 46684a40a8020 |
12 | 1752955759056 |
13 | 809a3cb022c9 |
14 | 37cd51143282 |
15 | 1a09a877bdcc |
hex | d22567ef602 |
14441131210242 has 32 divisors (see below), whose sum is σ = 31520371809024. Its totient is φ = 4374371315600.
The previous prime is 14441131210223. The next prime is 14441131210249. The reversal of 14441131210242 is 24201213114441.
14441131210242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (14441131210249) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43057968 + ... + 43392059.
It is an arithmetic number, because the mean of its divisors is an integer number (985011619032).
Almost surely, 214441131210242 is an apocalyptic number.
14441131210242 is an abundant number, since it is smaller than the sum of its proper divisors (17079240598782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14441131210242 is a wasteful number, since it uses less digits than its factorization.
14441131210242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86452574.
The product of its (nonzero) digits is 6144, while the sum is 30.
Adding to 14441131210242 its reverse (24201213114441), we get a palindrome (38642344324683).
The spelling of 14441131210242 in words is "fourteen trillion, four hundred forty-one billion, one hundred thirty-one million, two hundred ten thousand, two hundred forty-two".
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