Base | Representation |
---|---|
bin | 1101001000100101110100… |
… | …1011011010111001100011 |
3 | 1220010120101002002021010222 |
4 | 3102021131023122321203 |
5 | 3343101131242332003 |
6 | 50414114322513255 |
7 | 3020226320621516 |
oct | 322113513327143 |
9 | 56116332067128 |
10 | 14441243324003 |
11 | 4668551412821 |
12 | 175298720582b |
13 | 809a5a0c7802 |
14 | 37cd61da8d7d |
15 | 1a09b3525c38 |
hex | d225d2dae63 |
14441243324003 has 2 divisors, whose sum is σ = 14441243324004. Its totient is φ = 14441243324002.
The previous prime is 14441243323993. The next prime is 14441243324077. The reversal of 14441243324003 is 30042334214441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14441243324003 - 26 = 14441243323939 is a prime.
It is a super-2 number, since 2×144412433240032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14441243324093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220621662001 + 7220621662002.
It is an arithmetic number, because the mean of its divisors is an integer number (7220621662002).
Almost surely, 214441243324003 is an apocalyptic number.
14441243324003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14441243324003 is an equidigital number, since it uses as much as digits as its factorization.
14441243324003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 14441243324003 its reverse (30042334214441), we get a palindrome (44483577538444).
The spelling of 14441243324003 in words is "fourteen trillion, four hundred forty-one billion, two hundred forty-three million, three hundred twenty-four thousand, three".
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