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144421000333 is a prime number
BaseRepresentation
bin1000011010000000101…
…0011001010010001101
3111210202221120222002021
42012200022121102031
54331233234002313
6150202431130141
713301613151051
oct2064012312215
9453687528067
10144421000333
1156280987125
1223ba6373951
131080779881c
146dc0851c61
153b53e0778d
hex21a029948d

144421000333 has 2 divisors, whose sum is σ = 144421000334. Its totient is φ = 144421000332.

The previous prime is 144421000313. The next prime is 144421000351. The reversal of 144421000333 is 333000124441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81280869604 + 63140130729 = 285098^2 + 251277^2 .

It is a cyclic number.

It is not a de Polignac number, because 144421000333 - 229 = 143884129421 is a prime.

It is a super-2 number, since 2×1444210003332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144421000298 and 144421000307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144421000313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72210500166 + 72210500167.

It is an arithmetic number, because the mean of its divisors is an integer number (72210500167).

Almost surely, 2144421000333 is an apocalyptic number.

It is an amenable number.

144421000333 is a deficient number, since it is larger than the sum of its proper divisors (1).

144421000333 is an equidigital number, since it uses as much as digits as its factorization.

144421000333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 144421000333 its reverse (333000124441), we get a palindrome (477421124774).

The spelling of 144421000333 in words is "one hundred forty-four billion, four hundred twenty-one million, three hundred thirty-three", and thus it is an aban number.