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1444220131 is a prime number
BaseRepresentation
bin101011000010101…
…0000110011100011
310201122112222120111
41112011100303203
510424210021011
6355150352151
750534445214
oct12605206343
93648488514
101444220131
11681251a62
123437bb657
131a0292133
14d9b4340b
1586bcc121
hex56150ce3

1444220131 has 2 divisors, whose sum is σ = 1444220132. Its totient is φ = 1444220130.

The previous prime is 1444220123. The next prime is 1444220137. The reversal of 1444220131 is 1310224441.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1310224441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1444220131 - 23 = 1444220123 is a prime.

It is a super-2 number, since 2×14442201312 = 4171543573571314322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1444220137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722110065 + 722110066.

It is an arithmetic number, because the mean of its divisors is an integer number (722110066).

Almost surely, 21444220131 is an apocalyptic number.

1444220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1444220131 is an equidigital number, since it uses as much as digits as its factorization.

1444220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

The square root of 1444220131 is about 38002.8963501468. The cubic root of 1444220131 is about 1130.3452963611.

Adding to 1444220131 its reverse (1310224441), we get a palindrome (2754444572).

The spelling of 1444220131 in words is "one billion, four hundred forty-four million, two hundred twenty thousand, one hundred thirty-one".