Search a number
-
+
14443015872853 is a prime number
BaseRepresentation
bin1101001000101100011011…
…0101001010000101010101
31220010201221121110002001101
43102023012311022011111
53343113244030412403
650415010242430101
73020321253214441
oct322130665120525
956121847402041
1014443015872853
114669280a27a27
1217531a0962331
13809c803c5a99
1437d08d577821
151a0a68e5a71d
hexd22c6d4a155

14443015872853 has 2 divisors, whose sum is σ = 14443015872854. Its totient is φ = 14443015872852.

The previous prime is 14443015872809. The next prime is 14443015872877. The reversal of 14443015872853 is 35827851034441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8040587661649 + 6402428211204 = 2835593^2 + 2530302^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14443015872853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14443015872794 and 14443015872803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14443015872053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221507936426 + 7221507936427.

It is an arithmetic number, because the mean of its divisors is an integer number (7221507936427).

Almost surely, 214443015872853 is an apocalyptic number.

It is an amenable number.

14443015872853 is a deficient number, since it is larger than the sum of its proper divisors (1).

14443015872853 is an equidigital number, since it uses as much as digits as its factorization.

14443015872853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12902400, while the sum is 55.

The spelling of 14443015872853 in words is "fourteen trillion, four hundred forty-three billion, fifteen million, eight hundred seventy-two thousand, eight hundred fifty-three".