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144432335436397 is a prime number
BaseRepresentation
bin100000110101110001000110…
…000011000011101001101101
3200221101121002210022222100121
4200311301012003003221231
5122412334410332431042
61231103144321524541
742264614625623431
oct4065610603035155
9627347083288317
10144432335436397
1142025456013168
1214247b54aa3751
136278bac010c88
1427947c308c9c1
1511a703aa3a367
hex835c460c3a6d

144432335436397 has 2 divisors, whose sum is σ = 144432335436398. Its totient is φ = 144432335436396.

The previous prime is 144432335436247. The next prime is 144432335436437. The reversal of 144432335436397 is 793634533234441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73919602717801 + 70512732718596 = 8597651^2 + 8397186^2 .

It is a cyclic number.

It is not a de Polignac number, because 144432335436397 - 219 = 144432334912109 is a prime.

It is a super-2 number, since 2×1444323354363972 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144432335436097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72216167718198 + 72216167718199.

It is an arithmetic number, because the mean of its divisors is an integer number (72216167718199).

Almost surely, 2144432335436397 is an apocalyptic number.

It is an amenable number.

144432335436397 is a deficient number, since it is larger than the sum of its proper divisors (1).

144432335436397 is an equidigital number, since it uses as much as digits as its factorization.

144432335436397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 235146240, while the sum is 61.

The spelling of 144432335436397 in words is "one hundred forty-four trillion, four hundred thirty-two billion, three hundred thirty-five million, four hundred thirty-six thousand, three hundred ninety-seven".