Base | Representation |
---|---|
bin | 100000110101110001000110… |
… | …000011000011101010010010 |
3 | 200221101121002210022222101222 |
4 | 200311301012003003222102 |
5 | 122412334410332431214 |
6 | 1231103144321525042 |
7 | 42264614625623513 |
oct | 4065610603035222 |
9 | 627347083288358 |
10 | 144432335436434 |
11 | 420254560131a1 |
12 | 14247b54aa3782 |
13 | 6278bac010cb6 |
14 | 27947c308ca0a |
15 | 11a703aa3a38e |
hex | 835c460c3a92 |
144432335436434 has 4 divisors (see below), whose sum is σ = 216648503154654. Its totient is φ = 72216167718216.
The previous prime is 144432335436397. The next prime is 144432335436437. The reversal of 144432335436434 is 434634533234441.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 122138857206025 + 22293478230409 = 11051645^2 + 4721597^2 .
It is not an unprimeable number, because it can be changed into a prime (144432335436437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36108083859107 + ... + 36108083859110.
Almost surely, 2144432335436434 is an apocalyptic number.
144432335436434 is a deficient number, since it is larger than the sum of its proper divisors (72216167718220).
144432335436434 is an equidigital number, since it uses as much as digits as its factorization.
144432335436434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72216167718219.
The product of its digits is 59719680, while the sum is 53.
The spelling of 144432335436434 in words is "one hundred forty-four trillion, four hundred thirty-two billion, three hundred thirty-five million, four hundred thirty-six thousand, four hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •