Base | Representation |
---|---|
bin | 10101000001001001010… |
… | …001110011110101111011 |
3 | 12010002002102112202022011 |
4 | 111001021101303311323 |
5 | 142131001113321034 |
6 | 3023304144510351 |
7 | 206231023656661 |
oct | 25011121636573 |
9 | 5102072482264 |
10 | 1444338417019 |
11 | 5075a4423243 |
12 | 1b3b0a01b3b7 |
13 | a627b739aa4 |
14 | 4dc99060c31 |
15 | 27885968864 |
hex | 15049473d7b |
1444338417019 has 2 divisors, whose sum is σ = 1444338417020. Its totient is φ = 1444338417018.
The previous prime is 1444338416977. The next prime is 1444338417061. The reversal of 1444338417019 is 9107148334441.
It is a balanced prime because it is at equal distance from previous prime (1444338416977) and next prime (1444338417061).
It is an emirp because it is prime and its reverse (9107148334441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1444338417019 - 217 = 1444338285947 is a prime.
It is a super-2 number, since 2×14443384170192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1444338417419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722169208509 + 722169208510.
It is an arithmetic number, because the mean of its divisors is an integer number (722169208510).
Almost surely, 21444338417019 is an apocalyptic number.
1444338417019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1444338417019 is an equidigital number, since it uses as much as digits as its factorization.
1444338417019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1161216, while the sum is 49.
The spelling of 1444338417019 in words is "one trillion, four hundred forty-four billion, three hundred thirty-eight million, four hundred seventeen thousand, nineteen".
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