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14444112100123 is a prime number
BaseRepresentation
bin1101001000110000100000…
…1010111011101100011011
31220010211210000012012011101
43102030020022323230123
53343123020144200443
650415311122412231
73020360364045346
oct322141012735433
956124700165141
1014444112100123
1146697937a5782
121753447b01077
1380a0c6555484
1437d154db345d
151a0ad02e884d
hexd23082bbb1b

14444112100123 has 2 divisors, whose sum is σ = 14444112100124. Its totient is φ = 14444112100122.

The previous prime is 14444112100111. The next prime is 14444112100139. The reversal of 14444112100123 is 32100121144441.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14444112100123 - 213 = 14444112091931 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14444112100091 and 14444112100100.

It is not a weakly prime, because it can be changed into another prime (14444112100153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222056050061 + 7222056050062.

It is an arithmetic number, because the mean of its divisors is an integer number (7222056050062).

Almost surely, 214444112100123 is an apocalyptic number.

14444112100123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14444112100123 is an equidigital number, since it uses as much as digits as its factorization.

14444112100123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 14444112100123 its reverse (32100121144441), we get a palindrome (46544233244564).

The spelling of 14444112100123 in words is "fourteen trillion, four hundred forty-four billion, one hundred twelve million, one hundred thousand, one hundred twenty-three".