Base | Representation |
---|---|
bin | 10101000001010001110… |
… | …000111111010001100101 |
3 | 12010002110100110222001120 |
4 | 111001101300333101211 |
5 | 142131244041324122 |
6 | 3023330232444153 |
7 | 206234403166101 |
oct | 25012160772145 |
9 | 5102410428046 |
10 | 1444480808037 |
11 | 507667838773 |
12 | 1b3b49849659 |
13 | a62a20a3527 |
14 | 4dcadd28901 |
15 | 278931e375c |
hex | 15051c3f465 |
1444480808037 has 4 divisors (see below), whose sum is σ = 1925974410720. Its totient is φ = 962987205356.
The previous prime is 1444480807997. The next prime is 1444480808047. The reversal of 1444480808037 is 7308080844441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1444480808037 - 27 = 1444480807909 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1444480808047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240746801337 + ... + 240746801342.
It is an arithmetic number, because the mean of its divisors is an integer number (481493602680).
Almost surely, 21444480808037 is an apocalyptic number.
It is an amenable number.
1444480808037 is a deficient number, since it is larger than the sum of its proper divisors (481493602683).
1444480808037 is an equidigital number, since it uses as much as digits as its factorization.
1444480808037 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 481493602682.
The product of its (nonzero) digits is 2752512, while the sum is 51.
The spelling of 1444480808037 in words is "one trillion, four hundred forty-four billion, four hundred eighty million, eight hundred eight thousand, thirty-seven".
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