Search a number
-
+
144455110261433 is a prime number
BaseRepresentation
bin100000110110000110010011…
…100010000111101010111001
3200221110202220000011221221222
4200312012103202013222321
5122413223031211331213
61231121432253241425
742266352203504306
oct4066062342075271
9627422800157858
10144455110261433
1142034082895314
1214250450193275
13627b09b5400ca
142795943ac40ad
1511a79201bb808
hex836193887ab9

144455110261433 has 2 divisors, whose sum is σ = 144455110261434. Its totient is φ = 144455110261432.

The previous prime is 144455110261391. The next prime is 144455110261439. The reversal of 144455110261433 is 334162011554441.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123648995739049 + 20806114522384 = 11119757^2 + 4561372^2 .

It is a cyclic number.

It is not a de Polignac number, because 144455110261433 - 214 = 144455110245049 is a prime.

It is a super-2 number, since 2×1444551102614332 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (144455110261439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72227555130716 + 72227555130717.

It is an arithmetic number, because the mean of its divisors is an integer number (72227555130717).

Almost surely, 2144455110261433 is an apocalyptic number.

It is an amenable number.

144455110261433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144455110261433 is an equidigital number, since it uses as much as digits as its factorization.

144455110261433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 691200, while the sum is 44.

The spelling of 144455110261433 in words is "one hundred forty-four trillion, four hundred fifty-five billion, one hundred ten million, two hundred sixty-one thousand, four hundred thirty-three".