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144521254021 is a prime number
BaseRepresentation
bin1000011010011000100…
…0110101010010000101
3111211000221020101021211
42012212020311102011
54331434420112041
6150220412011421
713304241250624
oct2064610652205
9454027211254
10144521254021
1156322531211
1224013a60b71
131082249a931
146dcdcab6bb
153b5cb0c481
hex21a6235485

144521254021 has 2 divisors, whose sum is σ = 144521254022. Its totient is φ = 144521254020.

The previous prime is 144521254001. The next prime is 144521254039. The reversal of 144521254021 is 120452125441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138075412225 + 6445841796 = 371585^2 + 80286^2 .

It is a cyclic number.

It is not a de Polignac number, because 144521254021 - 225 = 144487699589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144521254001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72260627010 + 72260627011.

It is an arithmetic number, because the mean of its divisors is an integer number (72260627011).

Almost surely, 2144521254021 is an apocalyptic number.

It is an amenable number.

144521254021 is a deficient number, since it is larger than the sum of its proper divisors (1).

144521254021 is an equidigital number, since it uses as much as digits as its factorization.

144521254021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 144521254021 its reverse (120452125441), we get a palindrome (264973379462).

The spelling of 144521254021 in words is "one hundred forty-four billion, five hundred twenty-one million, two hundred fifty-four thousand, twenty-one".